1.
Diketahui network awal 192.168.11.0/23 Buatlah menjadi 16
subnetwork !
Jawab :
Total
host tersedia : 232-23 = 29=
512 Host
Host
per Subnet : 512 : 16 = 32
Host per subnet
Bit
yang ditambah : 16
= 24 , 4 Bit yang ditambah
Network
Address : 192.168.10.0
Broadcast
Address : 192.168.11.255
Subnet :
1) 192.168.10.0/27
2) 192.168.10.32/27
3) 192.168.10.64/27
4) 192.168.10.96/27
5) 192.168.10.128/27
6) 192.168.10.160/27
7) 192.168.10.192/27
8) 192.168.10.224/27 à 192.168.10.255/27
9) 192.168.11.0/27
10)192.168.11.32/27
11)192.168.11.64/27
12)192.168.11.96/27
13)192.168.11.128/27
14)192.168.11.160/27
15)192.168.11.192/27
16)192.168.11.224/27 à 192.168.11.255/27
2.
Network awal 192.168.10.14 /26. Buatlah menjadi 7
subnetwork!
Jawab :
Total
host tersedia : 232-26 = 26=
64 Host
Host
per Subnet : 64 : 8 = 8
Host per subnet
Bit
yang ditambah : 8 =
23 , 3 Bit yang ditambah
Network
Address : 192.168.10.0
Broadcast
Address : 192.168.10.64
Subnet :
1) 192.168.10.0/29
2) 192.168.10.8/29
3) 192.168.10.16/29
4) 192.168.10.24/29
5) 192.168.10.32/29
6) 192.168.10.40/29
7) 192.168.10.48/29
8) 192.168.10.56/29 à 192.168.10.64/29
3.
Network awal 192.168.112.0 /20 , tentukan
alokasi subnetwork yang masing - masing terdiri atas 600 host!
Jawab
:
Total
host tersedia : 232-20 = 212=
4096 Host
Host
per Subnet : 4096 : 1024
= 4 Host per subnet
Bit
yang ditambah : 4 =
22 , 2 Bit yang ditambah
Network
Address : 192.168.0.0
Broadcast
Address : 192.168.0.255
Subnet :
1) 192.168. 0.0/22
2) 192.168.4.255/22
3) 192.168.8.255/22
4) 192.168.12.255/22 à 192.168.16.255/22
4.
Network awal 100.100.10.10 /28 , tentukan
alokasi subnetwork yang masing - masing terdiri atas 8 host!
Jawab
:
Total
host tersedia : 232-28 = 24=
16 Host
Subnet : 16 : 8 = 2 subnet
Bit
yang ditambah : 2 =
21 , 1 Bit yang ditambah
Network
Address : 100.100.10.0
Broadcast
Address : 100.100.10.16
Subnet :
1) 100.100.10.0/29
2) 100.100.10.8/29 à 100.100.10.16/29
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